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cx^2+bx+c=0 find b:c |
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Answer» Cx²+bx+C = 0 so, x² +(b/c)x+1 = 0 , D = b²/c²-4 roots are x = -b/2c ± √(b²-4)/2c so , b/c = -( sum of roots) b: c = - sum of roots :1 |
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