1.

Current passing through galvanometer is 0.002A and resistance galvanometer is Rg = 50Ω. Find out shut resistance to convert it into ammeter of range 0.5A.(1) 0.5Ω(2) 0.2Ω(3) 0.7Ω(4) 0.9Ω

Answer»

The correct option (2) 0.2Ω  

Explanation:

Rs = IgRg/(I - Ig

= (2 x 10-3 x 50)/(0.5 - 2 x 10-3

= 0.31/0.498 = 0.2Ω



Discussion

No Comment Found

Related InterviewSolutions