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Current in a circuit falls form 0.5 A to 0.0 A in 0.1 s. If an average e.m.f. of 200 V is induced, give an estimate of the self inductance of the circuit ? |
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Answer» Here, `(dI)/(dt) = ((I_(2) - I_(1)))/(t) = (0.0 - 0.5)/(0.1) = - 50 As^(-1), e = 200 V, L = ?` As `|e| = L |(dI)/(dt)| :. L = (|e|)/(|dI // dt|) = (200)/(50) = 4 H` |
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