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Current amplification factor of a common base configuration is `0.88`. Find the value of base current when the emitter current is `1 m A`. |
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Answer» In a common-base arrangement, the current amplification factor `alpha =((Delta I_(C))/(Delta I_(E)))_(V_(CB)) = (I_(C))/(I_(E))` Given `alpha = 0.88, I_(E) = 1 mA` `:.` Collector current `I_(C) = alpha I_(E) = 0.88 xx 1 = 0.88 mA` Now since `I_(E)=I_(B) + I_(C)` `:.` Base current `I_(B) =I_(E) -I_(C) = 1 - 0.88 = 0.12 mA`. |
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