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`Cu^(+) + e rarr Cu, E^(@) = X_(1)` volt, `Cu^(2+) + 2e rarr Cu, E^(@) = X_(2)`X_(2) volt For `Cu^(2+) + e rarr Cu^(+), E^(@)` will be :A. `x_(1) -2x_(2)`B. `x_(1)+2x_(2)`C. `x_(1)-x_(2)`D. `2x_(2)-x_(1)` |
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Answer» Correct Answer - D `Cu^(+)+e^(-)rarr Cu Delta G_(1)= -F E^(@)= -FX_(1)` `Cu^(2+)+2e^(-)rarr Cu Delta G_(2)= -2F E^(@)= -2 FX_(2)` `Cu^(2+)+e^(-)rarr Cu^(+) Delta G_(3)= -2F E^(@)= -2 FX_(2)` `Delta G_(3) = Delta G_(2)-Delta G_(1) -F E^(@)= -2 FX_(2)+FX_(1)` `E^(@)=2X_(2)-X_(1)` |
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