CThe height of an equilateraf a measure9J3 Find its area.

1.	CThe height of an equilateraf a measure9J3 Find its area.
Answer» $\huge \bigstar ★ \huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}★★$ We know that Height of an equilateral triangle = √3/2 a It is given that height = 9CM So we get √3/2 a = 9 On further CALCULATION a = (9 × 2)/ √3 Multiplying both numerator and denominator by √3 We get a = (9 × 2 × √3) / (√3 × √3) So we get BASE = a = 6√3cm We know that the area of an equilateral triangle = ½ × b × h By substituting the values Area of the equilateral triangle = ½ × 6√3 × 9 On further calculation Area of the equilateral triangle = 27√3 cm2 By substituting the value of √3 Area of the equilateral triangle = 27 × 1.732 = 46.764 By correcting to 2 places of decimal Area of the equilateral triangle = 46.76 cm2 Therefore, the area of an equilateral triangle = 46.76 cm2. ${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$

Answer»

$\huge \bigstar ★ \huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}★★$

We know that

Height of an equilateral triangle = √3/2 a

It is given that height = 9CM

So we get

√3/2 a = 9

On further CALCULATION a = (9 × 2)/ √3

Multiplying both numerator and denominator by √3

We get

a = (9 × 2 × √3) / (√3 × √3)

So we get

BASE = a = 6√3cm

We know that the area of an equilateral triangle = ½ × b × h

By substituting the values

Area of the equilateral triangle = ½ × 6√3 × 9

On further calculation

Area of the equilateral triangle = 27√3 cm2

By substituting the value of √3

Area of the equilateral triangle = 27 × 1.732 = 46.764

By correcting to 2 places of decimal

Area of the equilateral triangle = 46.76 cm2

Therefore, the area of an equilateral triangle = 46.76 cm2.

${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$

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