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cot 250tan 65耳何何ATTeTQ : (cos? 20° + cos? 70°) +cot 5° cot 10° cot 60cot 80° cot 85° |
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Answer» cos²20+cos²70+cot25/tan65+cot5cot10cot60cot80cot85 =cos²20+(sin20)²+tan65/tan65+cot5cot10cot60tan10tan5 =since cos²x+sin²x=1 1+1+cot60 2+1/√3 Like my answer if you find it useful! |
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