1.

∫cosx+xsinxx(x+cosx)dx=ln∣∣∣xx+f(x)∣∣∣+C, then the value of f(π2)+1 is equal to(where C is constant of integration)

Answer» cosx+xsinxx(x+cosx)dx=lnxx+f(x)+C, then the value of f(π2)+1 is equal to

(where C is constant of integration)


Discussion

No Comment Found