1.

(cosec theta + sin theta) (cosec theta - sin theta) = (cot^2theta + cos^2 theta)

Answer»

This can be WRITTEN as
(cosec²Q-Sin²Q).
USING a²-b²=(a+b)(a-b)
((1+cot²Q)-(1-cos²Q))
(1+cot²Q-1+cos²Q)
(cot²Q-cos²Q)
HOPE this HELPS..



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