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(cosec*theta %2B cot(theta) - 1)/(-cosec*theta %2B cot(theta) %2B 1)=cosec*theta %2B cot(theta) |
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Answer» Let theta = x LHS: (cotx+cosecx)-1/(cotx-cosecx+1) =(cosecx+cotx)-(cosec²x-cot²x)/(cotx-cosecx+1) = (cosecx+cotx)[1-(cosecx-cotx)]/(cotx-cosecx+1) = (cosecx+cotx)(cotx-cosecx+1)/(cotx-cosecx+1) = (cosecx+cotx) = RHS Hence proved |
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