1.

Cosec square theta+ root 3 cot theta -7=0

Answer»

ANSWER:

we KNOW,

1 +  {<klux>COT</klux>}^{<klux>2</klux>} theta =  {cosec}^{2} \: theta

1 + cot^2 theta + √3 cot theta - 7=0

let cot theta = x

(x)^2 + √3x - 6 = 0

↪(x )^2 +2√3x - √3x - 6 = 0

↪x ( x + 2√3 ) - √3 ( x + 2√3 ) = 0

↪( x - √3 ) ( x + 2√3 )

↪ x = √3 OR x = -2√3

Therefor

cot theta = √3 OR cot theta = -2/√3



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