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cosec 28-sec20cos ec2θ + sec2 θ22. If cot θ--/7, show that |
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Answer» cott = √7 cosect = 2√2 sect = 2√2/√7 (cosect*cosect-sect*sect)/(cosect*cosect+sect*sect) = (2√2*2√2 - 2√2*2√2/(√7*√7))/(2√2*2√2 + 2√2*2√2/(√7*√7)) = (8-8/7)/(8+8/7) = (56-8)/(56+8) = 48/64 = 3/4 |
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