1.

(cosA/(1+sinA ))+(1+SinA)/cosA)=2secA​

Answer» ONG>Step-by-step explanation:

LHS =COSA/(1+sinA) +(1+sinA)/cosA

={cos²A +(1+sinA)²}/cosA.(1+sinA)

={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)

use sin²∅ +cos²∅ =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/cosA

=2secA

please make me BRAINLIST Dear and FOLLOW me on



Discussion

No Comment Found

Related InterviewSolutions