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(cosA/(1+sinA ))+(1+SinA)/cosA)=2secA |
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Answer» ONG>Step-by-step explanation: LHS =COSA/(1+sinA) +(1+sinA)/cosA ={cos²A +(1+sinA)²}/cosA.(1+sinA) ={cos²A+1+sin²A+2sinA}/cosA.(1+sinA) use sin²∅ +cos²∅ =1 =(1+1+2sinA)/cosA(1+sinA) =2(1+sinA)/cosA(1+sinA) =2/cosA =2secA please make me BRAINLIST Dear and FOLLOW me on
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