Cos44°×cos16° - sin44×sin16 =

1.	Cos44°×cos16° - sin44×sin16 =
Answer» SOLUTION TO DETERMINE The value of COS 44° × cos 16° - sin 44° × sin 16° FORMULA TO BE IMPLEMENTED We are aware of the Trigonometric formula that cos ( X + y ) = cos x cos y - sin x sin y EVALUATION We know that cos ( x + y ) = cos x cos y - sin x sin y Taking x = 44° & y = 16° we GET cos 44° × cos 16° - sin 44° × sin 16° = cos ( 44° + 16° ) = cos 60° $\displaystyle\sf{ = \frac{<klux>1</klux>}{2} }$ ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. If cosθ+secθ=√2,find the value of cos²θ+sec²θ brainly.in/question/25478419 2. Value of 3 + cot 80 cot 20/cot80+cot20 is EQUAL to brainly.in/question/17024513 3. In a triangle, prove that (b+c-a)(cotB/2+cotC/2)=2a×cotA/2 brainly.in/question/19793971

Answer»

SOLUTION

TO DETERMINE

The value of

COS 44° × cos 16° - sin 44° × sin 16°

FORMULA TO BE IMPLEMENTED

We are aware of the Trigonometric formula that

cos ( X + y ) = cos x cos y - sin x sin y

EVALUATION

We know that

cos ( x + y ) = cos x cos y - sin x sin y

Taking x = 44° & y = 16° we GET

cos 44° × cos 16° - sin 44° × sin 16°

= cos ( 44° + 16° )

= cos 60°

$\displaystyle\sf{ = \frac{<klux>1</klux>}{2} }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. If cosθ+secθ=√2,find the value of cos²θ+sec²θ

brainly.in/question/25478419

2. Value of 3 + cot 80 cot 20/cot80+cot20 is EQUAL to

brainly.in/question/17024513

3. In a triangle, prove that (b+c-a)(cotB/2+cotC/2)=2a×cotA/2

brainly.in/question/19793971

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