(cos3a+cos7a+2cos5a)/(cosa+cos5a+2cos3a)=cos2a-sin2a.tan3a – InterviewSolution

1.	(cos3a+cos7a+2cos5a)/(cosa+cos5a+2cos3a)=cos2a-sin2a.tan3a
Answer» ONG>ANSWER: it is not a RIGHT answer of RHS

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