1.

∫cos2x-cos2θcosx-cosθdx is equal to(a) 2sinx+xcosθ+C(b) 2sinx-xcosθ+C(c) 2sinx+2xcosθ+C(d) 2sinx-2xcosθ+C

Answer» cos2x-cos2θcosx-cosθdx is equal to



(a) 2sinx+xcosθ+C

(b) 2sinx-xcosθ+C

(c) 2sinx+2xcosθ+C

(d) 2sinx-2xcosθ+C


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