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∫cos2x-cos2θcosx-cosθdx is equal to(a) 2sinx+xcosθ+C(b) 2sinx-xcosθ+C(c) 2sinx+2xcosθ+C(d) 2sinx-2xcosθ+C |
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Answer» is equal to (a) (b) (c) (d) |
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