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( cos x - sin x )^ 2 = 1- sin 2 x |
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Answer» Answer: It depends on how far back you need to go in your proof. If you can use: sin 2 ( x ) + 2 ( x ) = 1 (which can be derived from the Pythagorean Theorem) and sin ( 2 x ) = 2 sin ( x ) ⋅ cos ( x ) (the Double Angle FORMULA for sin, which is considerably more complicate to prove) then the REQUESTED proof is fairly SIMPLE: ( sin ( x ) + cos ( x ) ) 2
= sin 2 ( x ) + 2 sin ( x ) ⋅ cos ( x ) + cos 2 ( x )
= [ sin 2 ( x ) + cos 2 ( x ) ] + 2 sin ( x ) ⋅ cos ( x )
= 1 + sin ( 2 x ) |
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