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| 1. |
Cos x/1-sinx = tan(Π/4+Π/2 |
| Answer» Solving LHS cosx/1-sinx=cosx/1-sinx multiplied by 1+sinx we get (cosx)(1+sinx)/1-sin^2x=cosx (1+sinx)/cos^2x=1+sinx/cosx=1/cosx+sinx/cosx=secx+tanx on RHS solving tan (pi/4+pi/2)=1 LHS is not equal to RHS | |