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Cos x= -1/3, x lies in third quadrant find sin x/2,cos x/2 and tan x/2 |
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Answer» Their is a problem tanx/2=root2 In third quadrant cosx is negative there 2cos^2x/2=1+cosx=1-1/3=2/3=2/6=root2/6 in 3rd quadrant cosx/2=-root2/6 and sinx/2=-2/root6 and tanx/2=1/root2 final answerSinx/2=-2/root6, cosx/2=-root (2/6), tanx/2=1/root2 |
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