1.

Cos theta +sin theta =√2 then cot =?​

Answer»

ider the given equation,

sinθ+cosθ=

2

…(1)

TAKING square both sides,

sin

2

θ+cos

2

θ+2sinθcosθ=2

1+2sinθcosθ=2

2sinθcosθ=1

sinθcosθ=

2

1

……(2)

Now, divided by cosθ in equation 1st , we GET

tanθ+1=

cosθ

2

….(3)

Again divided by sinθ in equation 1st, we get

1+cotθ=

sinθ

2

….(4)

ADD equation 1st and 2nd , we get

tanθ+cotθ+2=

cosθ

2

+

sinθ

2

tanθ+cotθ=

2

.(

sinθcosθ

sinθ+cosθ

)−2 ……(5)

Now, from equation 1st ,2nd and 5th ,we get

tanθ+cotθ=

2

.

⎝

⎜

⎜

⎛

2

1

2

⎠

⎟

⎟

⎞

−2

tanθ+cotθ=2


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