cos(theta)/(cosec*theta %2B 1) %2B cos(theta)/(cosec*theta - 1)=2*tan( – InterviewSolution

1.	cos(theta)/(cosectheta %2B 1) %2B cos(theta)/(cosectheta - 1)=2*tan(theta)
Answer» cosx/ cosecx+1 + cosx/ cosecx-1=cosx( cosecx-1)/cosecx^2-1 + cosx( cosecx-1)/ cosecx^2+1= cosx(1/ sinx-1 sinx)+cosx(1/ sinx+1)=Tanx + tanx=2 tanx

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