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\cos \theta=1 / 2, \text { find } \frac{\sec \theta+\csc \theta}{7-2 \sec \theta \cdot \csc \theta} |
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Answer» Cos theta = 1/2 = b/hb = 1, h = 2 , p= ?we know that,(h)² = (b)² + (p)²(p)² = (2)²-(1)²(p)² = 4-1p = ✓3cmTherefore,Sec theta = h/b = 2/1 tan theta = p/b = ✓3/1Cosec theta = h/p = 2/✓3Therefore,Sec theta + tan theta /7-2sec theta × Cosec theta.. give me full ans |
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