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Cos A minus root under 1 + sin 2A divided by sin a minus root under 1 + sin 2a |
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Answer» Answer: FIND the VALUE of 1+sin2A−1−sin2A1+sin2A+1−sin2A when ∣tanA∣<1 and ∣A∣ is acute A tanA Your Answer B −tanA C cotA Correct Answer D −cotA solution is COS A. Thanks for asking PLEASE follows me. |
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