cos (90° + θ) sec (-0) tan (1800-9)1.ve that: sec (360° -0) sin (18

1.	cos (90° + θ) sec (-0) tan (1800-9)1.ve that: sec (360° -0) sin (180 + 0) cot (90-)
Answer» cos(90+theeta)= sin thetasec theta= 1/cos thetacot theta= cos theta / sin thetatan theta= sin theta/ cos theta(sin theta/cos theta)tan theta--- numeratornow denominator = 1/cos(360- theta)(-sin theta) ( tan theta) 1/(-1)= -1as cos(-theta) = cos thetacot (90- theta) = tan theta

cos (90° + θ) sec (-0) tan (1800-9)1.ve that: sec (360° -0) sin (180 + 0) cot (90-)

Answer»

cos(90+theeta)= sin thetasec theta= 1/cos thetacot theta= cos theta / sin thetatan theta= sin theta/ cos theta(sin theta/cos theta)tan theta--- numeratornow denominator = 1/cos(360- theta)(-sin theta) ( tan theta)

1/(-1)= -1as cos(-theta) = cos thetacot (90- theta) = tan theta

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cos (90° + θ) sec (-0) tan (1800-9)1.ve that: sec (360° -0) sin (180 + 0) cot (90-)

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