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(cos 45)/(sec30+cosec30) |
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Answer» Step-by-step explanation: putting the value 1/root2 = ------------------------------ 2/root3+2 1/root 2 = ------------------------- 2+2root3 /root3 1. root 3 =------------- * ----------------- root 2. 2+2root3 root3 = ---------------------------- 2root2 +2root6 rationalise the denomenater root3*2root2-2root6 = ---------------------------------------- ( 2root2)squar - (2root6) squar answer is 3ROOT2 -root6/8
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