{cos (40-0)-sin(500-9))ья(a) 2cosO(iii)(b) 7sinθ(c) 0(d) 1 – InterviewSolution

1.

{cos (40-0)-sin(500-9))ья(a) 2cosO(iii)(b) 7sinθ(c) 0(d) 1

Answer»

sin(50+θ) - cos(40-θ)

= sin(50+θ) - sin[90-(40-θ)]

= sin(50+θ) - sin(90-40+θ)

= sin(50+θ) - sin(50+θ)

= 0

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