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cos 2θ cos 2ϕ + sin2(θ – ϕ) – sin2(θ + ϕ) is equal to(a) sin 2 (θ + ϕ)(b) cos 2 (θ + ϕ)(c) sin 2 (θ – ϕ)(d) cos 2 (θ – ϕ) |
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Answer» cos 2θ cos 2ϕ + sin2(θ – ϕ) – sin2(θ + ϕ) is equal to (a) sin 2 (θ + ϕ) (b) cos 2 (θ + ϕ) (c) sin 2 (θ – ϕ) (d) cos 2 (θ – ϕ) |
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