1.

cos 2θ cos 2ϕ + sin2(θ – ϕ) – sin2(θ + ϕ) is equal to(a) sin 2 (θ + ϕ)(b) cos 2 (θ + ϕ)(c) sin 2 (θ – ϕ)(d) cos 2 (θ – ϕ)

Answer» cos 2θ cos 2ϕ + sin2(θ – ϕ) – sin2(θ + ϕ) is equal to

(a) sin 2 (θ + ϕ)

(b) cos 2 (θ + ϕ)

(c) sin 2 (θ – ϕ)

(d) cos 2 (θ – ϕ)


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