Cos^2A+cosA=1 ; 4sin^2A+4sin^4A+2=?

1.	Cos^2A+cosA=1 ; 4sin^2A+4sin^4A+2=?
Answer» Answer: $cos {}^{2} \alpha + cos \alpha = 1$ $cos {}^{2} \alpha = 1 - cos \: \alpha$ $1 - sin {}^{2} \alpha = 1 - cos \: \alpha$ $cos \: \alpha = sin {}^{2} \alpha ......(i)$ Now we have to find, $4sin {}^{2} \alpha + 4sin {}^{4} \alpha + 2 =$ Using eq. (i) , $4 \cos( \alpha ) + 4 \cos {}^{2} ( \alpha ) + 2 = 4( \cos \alpha + \cos {}^{2} \alpha ) + 2 \: .......(ii)$ From given QUESTION, REPLACING the VALUE in eq. (ii) $4(1) + 2 = 6 \: \: ans.$ HOPE this helps you. Pls Mark BRAINLIEST. THANKS

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Answer:

$cos {}^{2} \alpha + cos \alpha = 1$