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Copper crystallizes into an fec lattice with edge length of 3.61 xx 10^(-8) cm. Calculate the density of copper. [Given" " Cu = 63.5 g mol^(-1), N_(A) = 6.022 xx 10^(23) mol^(-1)] |
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Answer» Solution :In fcc lattice `z=4, M="63.5 g MOL"^(-1),N_(A)=6.022xx10^(23)" mol"^(-1), a=3.61xx10^(-8)CM` `"Density d"=(zM)/(a^(3).N_(A))=(4xx63.5)/((3.61xx10^(-8))^(3)xx6.022xx10^(23))=(254)/(47.046xx10^(-24)xx6.022xx10^(23))` `=(254)/(283/311xx10^(-1))=(254)/(28.33)="8.965 g cm"^(-3)` |
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