Saved Bookmarks
| 1. |
Copper crystallises into a fee lattice. Its edge length is `3.62 xx 10^(-8)` cm. Calculate the density of copper (atomic mass of Cu=63-5 u, `N_A= 6-022 xx 10^(23) mol^(-1)`). |
|
Answer» Correct Answer - `8.9 "g cm"^(-3)` For fcc, `r=a/(2sqrt2) or a=2sqrt2r=2xx1.414xx128` pm =362 pm `rho=(ZxxM)/(a^3xxN_0)=(4xx63.5 "g mol"^(-1))/((362xx10^(-10)cm)^3xx6.02xx10^23 mol^(-1))=8.9 "g cm"^(-3)` Alternatively, `rho="Mass of unit cell "/"Volume of unit cell "=(4xx(63.5 "g mol"^(-1)//6.02xx10^23 mol^(-1)))/((362xx10^(-10)cm)^3)=8.9 g cm^(-3)` |
|