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Converted into polar form:1-i |
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Answer» ?if z lies in 1st quadrant then alpha = theta, 2nd quadrant then alpha =π-theta, 3rd quadrant then alpha = -(π-theta) and 4th quadrant then alpha = - theta. ? this will really help you?. z=x+iy. =1+i.x=1, y= -1. consider, x=rcos theta and y=rsin theta.--------eq (1) now r=root over x²+y²= root over 1²+(-1)²= √2. [r = √2].from eq (1).√2cos theta =1and √2sin theta= -1.cos theta=1/√2 & sin theta = -1/√2. as theta lies in 4th quadrant .α = - theta. theta = -1/√2= - π/4.α= - theta= - π/4. z=r(cos theta+i sin theta) . z=√2[cos(-π/4)+ i sin(-π/4). |
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