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Convert the variance of a product into a product of variances |
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Answer» Step-by-step explanation: Because X1X2⋯Xn−1 is a random variable and (ASSUMING all the Xi are independent) it is independent of Xn, the answer is obtained inductively: NOTHING new is NEEDED. Lest this SEEM too mysterious, the technique is no different than pointing out that since you can add TWO numbers with a calculator, you can add n numbers with the same calculator just by repeated addition |
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