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| 1. |
Convert following complex number into polar form3(Cos5π/3-i sinπ/6) |
| Answer» (5π/3) - 2π = -π/3 = -60 degreeHence cos (5π/3) = cos(-60) = +0.5Sin (π/6) = +0.5Hence 3(cos (5π/3)-i Sin (π/6))= 3(0.5 – 0.5i) = 1.5(1-i)Angle in argand plane = tan-1( y/x) = tan-1( -1/1)= -45 degree = -(π/4)Modulus of (1-i) = sqrt(2)Hence 3(cos (5π/3)-i Sin (π/6)) = 1.5 (1-i) = 1.5 * sqrt(2) [cos (-π/4)+isin (-π/4)] | |