Convert each of the following to its mole:a) 86.84 g of LiBr b)

1.	Convert each of the following to its mole:a) 86.84 g of LiBr b) 17.1 g of H2S c) 8.5 g of PH3
Answer» Here's your ANSWER mate 1) 86.84g of LiBr *Formula: n= GIVEN* mass ÷ molar mass Where n is NUMBER of moles. $n = 86.84 \div 7 + 80 \\ n = 86.84 \div 87 \\ n = 0.99 \: approx = 1moles\\ \\$ 2) 17.1g of H2S $n = 17.1 \div 1 \times 2 + 32 \\ n = 17.1 \div 34 \\ n = 0.5 \: moles$ 3) 8.5g of PH3 $n = 8.5 \div 40 + 1 \times 3 \\ n = 8.5 + 43 \\ n = 0.1moles$

Convert each of the following to its mole:a) 86.84 g of LiBr b) 17.1 g of H2S c) 8.5 g of PH3

Answer»

Here's your ANSWER mate

1) 86.84g of LiBr

Formula: n= GIVEN mass ÷ molar mass

Where n is NUMBER of moles.

$n = 86.84 \div 7 + 80 \\ n = 86.84 \div 87 \\ n = 0.99 \: approx = 1moles\\ \\$

2) 17.1g of H2S

$n = 17.1 \div 1 \times 2 + 32 \\ n = 17.1 \div 34 \\ n = 0.5 \: moles$

3) 8.5g of PH3

$n = 8.5 \div 40 + 1 \times 3 \\ n = 8.5 + 43 \\ n = 0.1moles$