1.

Construct the PQR such thatPQ=6-7cm, Q R = 5.8cmPR = 6-9 ch. Construct it'sincircle​

Answer»

Step-by-step explanation:

Let the centre of the CIRCLE be O.

AB = 12 cm

OC = 12 cm

OC ⊥ AB

We know PERPENDICULAR drawn from the centre of the circle to the chord, bisects the chord.

So, AC = 6 cm

In ⃤ OCA,

OC2+AC2=AO2⇒82+62=AO2⇒AO2=100⇒AO=10

Thus, AO = 10 cm

Diameter = 2 × 10 cm = 20 cm.



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