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Construct the PQR such thatPQ=6-7cm, Q R = 5.8cmPR = 6-9 ch. Construct it'sincircle |
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Answer» Step-by-step explanation: Let the centre of the CIRCLE be O. AB = 12 cm OC = 12 cm OC ⊥ AB We know PERPENDICULAR drawn from the centre of the circle to the chord, bisects the chord. So, AC = 6 cm In ⃤ OCA, OC2+AC2=AO2⇒82+62=AO2⇒AO2=100⇒AO=10 Thus, AO = 10 cm Diameter = 2 × 10 cm = 20 cm. |
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