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Construct ∆ PQR if it is given that PQ= 6cm , ∠RPQ = 300 and ∠ PQR = 1000. |
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Answer» EXAMPLE SUM Step-by-step explanation: Steps of Construction : (1) Draw a line PQ = 6 cm. (2) Using compass TAKING P as centre draw an angle ∠P = 60°. (3) Using compass taking Q as a centre draw an angle ∠Q = 30°. (4) PS and QT INTERSECT each other R. (5) ∆ RPQ is the required triangle. On measuring; ∠R = 90°, LENGTH of PR = 3 cm. |
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