1.

Construct ∆ PQR if it is given that PQ= 6cm , ∠RPQ = 300 and ∠ PQR = 1000.​

Answer»

ANSWER:

EXAMPLE SUM

Step-by-step explanation:

Steps of Construction :

(1) Draw a line PQ = 6 cm.

(2) Using compass TAKING P as centre draw an angle ∠P = 60°.

(3) Using compass taking Q as a centre draw an angle ∠Q = 30°.

(4) PS and QT INTERSECT each other R.

(5) ∆ RPQ is the required triangle.

On measuring; ∠R = 90°, LENGTH of PR = 3 cm.



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