Construct AXYZ in which YZ=4.1cm, 2Y=45, and XY+XZ 6.7 cm,

1.	Construct AXYZ in which YZ=4.1cm, 2Y=45, and XY+XZ 6.7 cm,
Answer» Steps of Construction :- Draw YZ = 4.1 cm Construct ∠ZYP = 45° Along YP, set off YQ = 6.7 cm Join ZQ Draw the Perpendicular BISECTOR of ZQ to INTERSECT YQ at X Join XZ Then, ΔABC is the Required Triangle . . . VERIFICATION :- On measuring, we find that - XY + YZ = (3.6 + 3.1) cm = 6.7 cm

Answer»

Steps of Construction :-

Draw YZ = 4.1 cm

Construct ∠ZYP = 45°

Along YP, set off YQ = 6.7 cm

Join ZQ

Draw the Perpendicular BISECTOR of ZQ to INTERSECT YQ at X

Join XZ

Then, ΔABC is the Required Triangle . . .

VERIFICATION :-

On measuring, we find that -

XY + YZ = (3.6 + 3.1) cm = 6.7 cm

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Construct AXYZ in which YZ=4.1cm, 2Y=45, and XY+XZ 6.7 cm, ​

Steps of Construction :-

Draw YZ = 4.1 cm

Construct ∠ZYP = 45°

Along YP, set off YQ = 6.7 cm

Join ZQ

Draw the Perpendicular BISECTOR of ZQ to INTERSECT YQ at X

Join XZ

Then, ΔABC is the Required Triangle . . .

VERIFICATION :-

On measuring, we find that -

XY + YZ = (3.6 + 3.1) cm = 6.7 cm

Discussion

No Comment Found

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Construct AXYZ in which YZ=4.1cm, 2Y=45, and XY+XZ 6.7 cm,