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Construct a triangle of 15 degre |
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Answer» ong>Answer: To construct 15^0 angle follow these steps: Draw a RAY L of any length. Taking CENTRE as O draw an arc with any radius to cut the line L. Label the intersecting POINT of L and the arc as B. Taking centre as B draw an arc with the same radius taken before to cut the previous arc at C. Join O and C and \angle COA=60^0 Draw an angle bisector OD to the \angle COA and \angle DOB=30^0 Draw an angle bisector OE to the \angle DOB and \angle EOB=15^0 is our required angle. Recommend (1) Comment (0) |
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