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Construct a trapezium PQRS with QR || PS and PQ = 2.8 cm,OR = 6.3 cm, PS = 4 cm and height of the trapezium = 2.5 cm. |
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Answer» In a trapezoid, PQRS, PQ is parallel to SR, ∴ ∠Q + ∠R = 180°⇒ 60° + ∠R = 180°⇒ ∠R = 180° - 75° = 105° Steps of construction: Step 1: Draw PQ = 2.8 cm.Step 2:At Q, draw ∠PQX = 105°.Step 3:From ray QX, cut off QR =6.3 cm.Step 4:At R, draw ∠QRY = 105°Step 5:From ray RY, cut off RS = 3.2cm.Step 6:Join SP. PQRS is the required trapezoid |
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