Construct a parallel line to a line AB from distance 4.7cm

1.	Construct a parallel line to a line AB from distance 4.7cm
Answer» Answer: Steps for construction, 1. Draw a LINE AB. 2. Take any two points P and Q on AB. 3. Construct angle BPE = angle BQF= 90 o 4. With P as center and radius equal to 3.5cm, cut PE at R. 5. With Q as center and radius equal to 3.5cm, cut QF at S. 6. Join CD and produce it on either side to get the required line CD parallel to AB and at a distance of 3CM from it.

Answer»

Answer:

Steps for construction,

1. Draw a LINE AB.

2. Take any two points P and Q on AB.

3. Construct angle BPE = angle BQF= 90

4. With P as center and radius equal to 3.5cm, cut PE at R.

5. With Q as center and radius equal to 3.5cm, cut QF at S.

6. Join CD and produce it on either side to get the required line CD parallel to AB and at a distance of 3CM from it.

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