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Construct a line through Q which parallel to X and Y |
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Answer» Step-by-step explanation: The POINT P=(p,Q)=(3,4) and a line is drawn parallel to Y-axis. Therefore, TH equation of the line is x=p=3 Again ANOTHER line is drawn parallel to X-axis through a point Q=(r,s)=(1,−7) Therefore, the equation of the line is y=s=−7 Therefore, the lines are x=3 and y=−7 Therefore, the point of intersection is (x,y)=(3,−7) |
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