1.

Construct a angel ABC in which AB=6cm ,BC=4cm,CA=5cm​

Answer»

ANSWER:

\tan( \alpha )  =  \frac{oppsite}{adjacent}

\tan( \alpha )  =  \frac{5}{4}

\cos( \beta )  =   \frac{adjacent}{hypotenuce}

\cos( \beta )  =  \frac{4}{6}

\cos( \beta )  =  \frac{2}{3}

The angle may be 90°



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