Consider the system shown in figure. We know the masses of bodies : m = 1 kg, M = 3 kg. The distance AB = BC = H//2 are covered in equal time intervals by the body of mass m and at B it undergoes an elastic collision with a stationary body of mass m_(0) (unknown). Time after this collision when the string in pu,,ey 2 becomes tight again is t_(0). t_(0) is second. t_(0)^(2) is equal to 1//x. Value of (x)/(10) is. (Given : H = 1m )

Consider the system shown in figure. We know the masses of bodies : m

1.	Consider the system shown in figure. We know the masses of bodies : m = 1 kg, M = 3 kg. The distance AB = BC = H//2 are covered in equal time intervals by the body of mass m and at B it undergoes an elastic collision with a stationary body of mass m_(0) (unknown). Time after this collision when the string in pu,,ey 2 becomes tight again is t_(0). t_(0) is second. t_(0)^(2) is equal to 1//x. Value of (x)/(10) is. (Given : H = 1m )
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