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Consider the situation in figure (18-E7). The bottom of the pot is a reflecting plane mirror, S is a small fish and T is a human eye. Refractive index of water is (a) At what distance(s) from itself will the fish see the image(s) of the eye ? (b) At what distance(s) from itself will the eye see the image(s) of the fish. |
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Answer» Let x = DISTANCE of the IMAGE of the eye FORMED above the surface as seen by the fishH/x = Real depth / APPARENT depth = 1/μx= hμso distance of direct image = H/2 + μH= H(μ +1/2)similarly image through mirror = H/2 +( H+x)3H/2 +μH=H(μ+3/2)B) H/2/ Y= uμy= H/2μwhere y= distance of image of fish below the surface direct image = H+y=H+H/2μ=H(1+1/2μ)Another image of fish will be formed H/2 below mirrorso real depth for hat image becomes =H+H/2= 3H/2apparent depth = 3H/2μso distance of image from eye= H+3H/ 2μ= H(1+3/2μ) |
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