Consider the reactions: 2S2O2−3(aq)+I2(s)→S4O2−6(aq)+2I−(aq)

1.	Consider the reactions: 2S2O2−3(aq)+I2(s)→S4O2−6(aq)+2I−(aq) S2O2−3(aq)+2Br2(l)+5H2O(l)→2SO2−4(aq)+4Br−(aq)+10H+(aq) Why does the same reductant, thiosulphate react differently with iodine and bromine?
Answer» Consider the reactions: $2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)$ $S_{2} O_{3}^{2 -} (a q) + 2 B r_{2} (l) + 5 H_{2} O (l) \to 2 S O_{4}^{2 -} (a q) + 4 B r^{-} (a q) + 10 H^{+} (a q)$ Why does the same reductant, thiosulphate react differently with iodine and bromine?

Consider the reactions: 2S2O2−3(aq)+I2(s)→S4O2−6(aq)+2I−(aq) S2O2−3(aq)+2Br2(l)+5H2O(l)→2SO2−4(aq)+4Br−(aq)+10H+(aq) Why does the same reductant, thiosulphate react differently with iodine and bromine?

Answer»

Consider the reactions:
$2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)$

$S_{2} O_{3}^{2 -} (a q) + 2 B r_{2} (l) + 5 H_{2} O (l) \to 2 S O_{4}^{2 -} (a q) + 4 B r^{-} (a q) + 10 H^{+} (a q)$
Why does the same reductant, thiosulphate react differently with iodine and bromine?

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Consider the reactions: 2S2O2−3(aq)+I2(s)→S4O2−6(aq)+2I−(aq) S2O2−3(aq)+2Br2(l)+5H2O(l)→2SO2−4(aq)+4Br−(aq)+10H+(aq) Why does the same reductant, thiosulphate react differently with iodine and bromine?

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