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Consider the reaction `:` `Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(3+)+7H_(2)O` What is the quantity of electricity in coulombs needed to reduce `1 mol e` of `Cr_(2)O_(7)^(2-)` ? |
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Answer» Correct Answer - `579000C` Form the given reactions, `1 mol of Cr_(2)O_(7)^(2-)` ions require `6F=6xx96500C=57900C` of electricity for reduction to `Cr^(3+)`. |
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