Consider the reaction: 4NO2(g) + O2(g) → 2N2O5(g), ΔrH = −111kJ.

1.	Consider the reaction: 4NO2(g) + O2(g) → 2N2O5(g), ΔrH = −111kJ. If N2O5(s) is formed instead of N2O5(g) in the above reaction, the ΔrH value will be: (given, ΔH of sublimation for N2O5 is 54 kJ mol−1)
Answer» Consider the reaction: $4 N O_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 k J$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be: (given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 k J m o l^{- 1}$ )

Consider the reaction: 4NO2(g) + O2(g) → 2N2O5(g), ΔrH = −111kJ. If N2O5(s) is formed instead of N2O5(g) in the above reaction, the ΔrH value will be: (given, ΔH of sublimation for N2O5 is 54 kJ mol−1)

Answer»

Consider the reaction:

$4 N O_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 k J$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be:

(given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 k J m o l^{- 1}$ )

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Consider the reaction: 4NO2(g) + O2(g) → 2N2O5(g), ΔrH = −111kJ. If N2O5(s) is formed instead of N2O5(g) in the above reaction, the ΔrH value will be: (given, ΔH of sublimation for N2O5 is 54 kJ mol−1)

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