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Consider the plane 2x + y + z = 0 and the point P(3, 5, 7). Then, the (A) foot of the perpendicular from P onto the given plane is (−3, 2, 4). (B) image of P in the given plane is (−9, −1, 1). (C) equation of the line joining the points (3, 5, 7) and (−9, −1, 1) is (x - 3)/6 = (y - 5)/6 = (z - 7)/4(D) distance of (−9, −1, 1) from the plane 2x + y + z = 0 is 9. |
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Answer» Correct option is (A),(B),(C) (A) foot of the perpendicular from P onto the given plane is (−3, 2, 4). (B) image of P in the given plane is (−9, −1, 1). (C) equation of the line joining the points (3, 5, 7) and (−9, −1, 1) is (x - 3)/6 = (y - 5)/6 = (z - 7)/4. |
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