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Consider the motion of the object whose velocity-time graph is given in the diagram belowa) What is the acceleration of the object between times t=0s and t= 2s?b) What is the acceleration of the object between times t= 10s and t=12 s?c) What is the net displacement of the object between times t=0s and t=16s. |
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Answer» Given : velocity-time graph of motion of the object To find : acceleration of the object between times t=0s and t= 2s , & t= 10s and t=12 s . net displacement of the object between times t=0s and t=16s Solution: Time sec Velocity m/s 0 0 2 8 10 8 12 4 16 4 acceleration of the object between times t=0s and t= 2s = ( 8 - 0)/(2 - 0) = 8/2 = 4 m/s² acceleration of the object between times t=10s and t= 12s = ( 4 - 8)/(12 - 10) = -4/2 = -2 m/s² the net displacement of the object between times t=0s and t=16s. = (1/2)(0 + 8)(2 - 0) + 8 (10 - 2) + (1/2)(8 + 4)(12 - 10) + 4(16 - 12) = 8 + 64 + 12 + 16 = 100 m acceleration of the object between times t=0s and t= 2s = 4 m/s² acceleration of the object between times t=10s and t= 12s = -2 m/s² net displacement of the object between times t=0s and t=16s. = 100 m Learn more: FIGURE given below SHOWS the graph of velocity v ofparticle MOVING ... Figure given below shows the graph of velocity v ofparticle moving ... The graph represents Jason's speed on a recent trip. For which time ... |
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