Consider the lung capacity to be `500 cm_(3)` and the pressure to ve equivalent of 761mm of HG, estimate the number of molecules per breath.

Consider the lung capacity to be `500 cm_(3)` and the pressure to ve e

1.	Consider the lung capacity to be `500 cm_(3)` and the pressure to ve equivalent of 761mm of HG, estimate the number of molecules per breath.
Answer» From ideal gas equation, `PV=NkappaT` Normal body temperature is `98.6^(0)F=37^(0)C=310K.` `N=(PV)/(kT)` `=((101.46)(500xx10^(-6)))/((1.3807xx10^(-23)xx310))` `=1.19xx10^(19)`molecules

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Consider the lung capacity to be `500 cm_(3)` and the pressure to ve equivalent of 761mm of HG, estimate the number of molecules per breath.

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